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Jennifer wrote the expression 5(3x + 1 + 2). Danielle used only the distributive property to write an equivalent expression. Which expression could Danielle have written?

 

5(3x + 3)
15x + 5x + 2x
15x + 5 + 10
15x + 15
 
 
 

Which expression is NOT equivalent to 4x + 12y?


16(x + y)
4(x + 3y)
2(2x + 6y)
(2x + 6y) + (2x + 6y)
 Dec 11, 2014

Best Answer 

 #1
avatar+23252 
+5

Using the distributive law on  5(3x + 1 + 2)

she would get:                      5(3x) + 5(1) + 5(2)

Can you get this next step?                                Don't do anything but these multiplications!

 

Use the distributive law on each of these:

16(x + y)  =  16(x) + 16(y)  =                                <--- can you make this look a little simpler?

4(x + 3y)  =  4(x) + 4(3y)  =                                  <--- can you make this look a little simpler?

2(2x + 6y)  =  2(2x) + 2(6y)  =                               <--- can you make this look a little simpler?

(2x + 6y) + (2x + 6y)  

   =  2x + 6y + 2x + 6y

         =  2x + 2x + 6y + 6y  =                                <--- can you make this look a little simpler?

Can you now pick out your answer?

 Dec 11, 2014
 #1
avatar+23252 
+5
Best Answer

Using the distributive law on  5(3x + 1 + 2)

she would get:                      5(3x) + 5(1) + 5(2)

Can you get this next step?                                Don't do anything but these multiplications!

 

Use the distributive law on each of these:

16(x + y)  =  16(x) + 16(y)  =                                <--- can you make this look a little simpler?

4(x + 3y)  =  4(x) + 4(3y)  =                                  <--- can you make this look a little simpler?

2(2x + 6y)  =  2(2x) + 2(6y)  =                               <--- can you make this look a little simpler?

(2x + 6y) + (2x + 6y)  

   =  2x + 6y + 2x + 6y

         =  2x + 2x + 6y + 6y  =                                <--- can you make this look a little simpler?

Can you now pick out your answer?

geno3141 Dec 11, 2014
 #2
avatar+449 
0

yes! thanks for the help! :)

 Dec 11, 2014

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