+117 1)Find the largest integer n for which 12^n evenly divides 20! .
2)Suppose that a, b, and c are real numbers for which
a^2*b^2=28
b^2*c^2=21
a^2*c^2=27
Multiple questions deleted - Melody.
+37153 From first equation b^2 = 28/a^2
From third equation c^2 = 27/a^2 Sub these into equation 2
28*27 / a4 =21
a = +- sqrt 6 =+-2.45
Sub this into the first equation to find b
then b = +- 2.16
then c = +- 2.12
Since a < b < c a = -2.45 b = -2.16 c = +- 2.12
3b then equal 3 * -2.16 = -6.48
