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A radiographic technique, using an exposure of 10mAmin, produces a film density of 1.5 where a film density of 2.3 is required. A film charactaristic curve is available which gives a log relative exposure value of 1.2 for [density = 1.5] with a correspondingvalue of 1.8 for [density = 2.3]the acceptable minimum film density should be achieved with an exposure of ?

 Aug 13, 2015

Best Answer 

 #1
avatar+33654 
+5

I'm guessing here, but:

 

log(10/k) = 1.2   so 10/k = 101.2 where k is a reference level exposure.

log(E/k) = 1.8     so E/k = 101.8 where E is the required exposure.

 

Divide the second of these by the first and rearrange to get:

 

E=10×101.8101.2E=39.8107170553497251

 

So E ≈ 39.8 mA.min

.

 Aug 13, 2015
 #1
avatar+33654 
+5
Best Answer

I'm guessing here, but:

 

log(10/k) = 1.2   so 10/k = 101.2 where k is a reference level exposure.

log(E/k) = 1.8     so E/k = 101.8 where E is the required exposure.

 

Divide the second of these by the first and rearrange to get:

 

E=10×101.8101.2E=39.8107170553497251

 

So E ≈ 39.8 mA.min

.

Alan Aug 13, 2015

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