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# area and perimter

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Find the area and perimeter of the rectangle graphed below.  Round your answers to the nearest hundredth. Mar 22, 2021

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Distance Formula = $$\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$

Im going to label the points for ease:

A(-6, 0) , B(2, 8) , C(6, 5) , D(-2, -3)

Now using the distance formula, we can find the dimensions of this rectangle.

AB = $$\sqrt{128} = 8\sqrt{2} ≈ 11.31$$

BC = $$\sqrt{25} = 5$$

CD = $$\sqrt{128} = 8\sqrt{2} ≈ 11.31$$

DA = $$\sqrt{25} = 5$$

(of course, since it's a rectangle, you could just find the dimensions of two of the sides)

This means the area of the rectangle is = $$8\sqrt{2} \cdot 5 = 40\sqrt{2} ​​≈ 56.57$$

And the perimeter is = $$2(8\sqrt{2} + 5) = 16\sqrt{2} + 10 ≈ 32.63$$

Mar 22, 2021
#2
+5 A graphed quadrilateral is NOT a rectangle!!! It's a parallelogram!!!

That parallelogram is inscribed in a rectangle that has an area of 132 sq units.

A = 132 - (64 + 12)

A = 56 sq units

jugoslav  Mar 22, 2021
edited by jugoslav  Mar 22, 2021
edited by jugoslav  Mar 22, 2021