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Find the area and perimeter of the rectangle graphed below.  Round your answers to the nearest hundredth.

 

 Mar 22, 2021
 #1
avatar+492 
0

Distance Formula = \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)

 

Im going to label the points for ease:

A(-6, 0) , B(2, 8) , C(6, 5) , D(-2, -3)

 

Now using the distance formula, we can find the dimensions of this rectangle. 

AB = \(\sqrt{128} = 8\sqrt{2} ≈ 11.31\)

BC = \(\sqrt{25} = 5\)

CD = \(\sqrt{128} = 8\sqrt{2} ≈ 11.31\)

DA = \(\sqrt{25} = 5\)

(of course, since it's a rectangle, you could just find the dimensions of two of the sides)

 

This means the area of the rectangle is = \(8\sqrt{2} \cdot 5 = 40\sqrt{2} ​​≈ 56.57 \)

 

And the perimeter is = \(2(8\sqrt{2} + 5) = 16\sqrt{2} + 10 ≈ 32.63 \)

 Mar 22, 2021
 #2
avatar+1164 
+5

cheekyA graphed quadrilateral is NOT a rectangle!!!cheeky       It's a parallelogram!!!

 

That parallelogram is inscribed in a rectangle that has an area of 132 sq units.

 

A = 132 - (64 + 12)

 

A = 56 sq units

jugoslav  Mar 22, 2021
edited by jugoslav  Mar 22, 2021
edited by jugoslav  Mar 22, 2021

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