+0  
 
0
44
3
avatar

Triangle ABC has its 3 altitudes H(a) =16, H(b) =18 and H(c) =20. What is the area of this triangle? Thank you.

 Jul 12, 2023
 #1
avatar
0

The area of a triangle is given by the formula:

area = (1/2)bh

where b is the base of the triangle and h is the height of the triangle.

In this case, we are given the heights of the triangle, so we can simply plug them into the formula to find the area.

area = (1/2)(H(a) + H(b) + H(c))

= (1/2)(16 + 18 + 20)

= 136

Therefore, the area of triangle ABC is 136.

 Jul 12, 2023
 #2
avatar
0

That is incorrect!  You are given only the altitudes of the triangle and no side is known.

Guest Jul 12, 2023
 #3
avatar
0

H==[1/16  +  1/18  + 1/20] / 2 ==0.0840277778

 

S ==4 * Sqrt[ H * (H - 1/16) * (H - 1/18) * (H - 1/20)]==0.00529539678

 

Area of the triangle==1 / 0.00529539678 ==188.84326 u^2

 Jul 13, 2023

2 Online Users