Triangle ABC has its 3 altitudes H(a) =16, H(b) =18 and H(c) =20. What is the area of this triangle? Thank you.
The area of a triangle is given by the formula:
area = (1/2)bh
where b is the base of the triangle and h is the height of the triangle.
In this case, we are given the heights of the triangle, so we can simply plug them into the formula to find the area.
area = (1/2)(H(a) + H(b) + H(c))
= (1/2)(16 + 18 + 20)
Therefore, the area of triangle ABC is 136.