The following scaled design is the layout of a hockey ring.The middle section is a rectangle with the sides of 6 and 8 inches . The end section are semi-circles . what is the are of the hokey rink
+129852 Well...it depends upon which sides of the rectangle the semi-circles abut
If they abut the 8 inch sides ....the area is [(6)(8) + pi*(4)^2] in^2 = about 98.27 in^2
If they abut the 6 inch sides ....the area is [(6)(8) + pi*(3)^2] in^2 = about 76.27 in^2
I don't know anything about hockey, so I don't know how the middle rectangle might be oriented !!!
