The area of a triangle is 124 square units? What would it new area be if its base was half as long and it height was three times as long?
+130514 We have :
(1/2)(b)(h) = 124
Now....half the base and treble the height
(1/2)(b/2)(3h) =
(1/2)(3/2)(b)(h)
So....the ratio of the area of the "new" triangle to the "old" =
[(1/2)(3/2)(b)(h)] / [(1/2)(b)(h)] = 3/2
So, the area of the "new" triangle = .....(3/2) * 124 = 186 units^2
+130514 We have :
(1/2)(b)(h) = 124
Now....half the base and treble the height
(1/2)(b/2)(3h) =
(1/2)(3/2)(b)(h)
So....the ratio of the area of the "new" triangle to the "old" =
[(1/2)(3/2)(b)(h)] / [(1/2)(b)(h)] = 3/2
So, the area of the "new" triangle = .....(3/2) * 124 = 186 units^2
