The arithmetic mean of 23, 16, 30, 33 and two other numbers that differ by 2 is 27. If the smallest of these 6 numbers is discarded, find the arithmetic mean of the remaining 5 numbers.
27 x 6 ==162 - sum of all 6 numbers
162 - 23 - 16 - 30 - 33 ==60 - sum of the missing 2 numbers.
60 / 2 ==30
30 + 1==31 - one of the missing 2 numbers
30 - 1 ==29 - the 2nd missing number
So, the 6 numbers are: 23, 16, 30, 33, 29, 31 ==162 - their total
162 - 16 ==146 / 5 ==29.20 - the average of the remaining 5 after removing the smallest.
