The sum of the fourth and eighth term of an arithmetic progression is 24, and the sum of the sixth and tenth terms is 44. FInd the first three terms of the arithmetic progression.
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Let x = 6th term 4th term is x-2d 8th is x+2d 10th is x + 4d
8th + 4th = 24
x-2d + x +2d = 24
2x = 24
x = 12
6th + 10th = 44
x + x + 4d = 44
2x+4d = 44
x + 2d = 22 12 + 2d = 22 so d = 5 6th term = 12 d = 5 can you take it from here?
