The sum of the 2nd and 7th terms of an A.P. is 30. Ifits 15th term is 1 less than twice its 8th term, find the AP
F + D + F + 6D =30,
F + 14D =2*[F+7D] - 1, solve for F, D
F =1 - This is the first term D =4 - This is the common difference.
AP =1, 5, 9, 13, 17, 21, 25, 29, 33, 37, 41, 45, 49, 53, 57.
