The fifth term of an arithmetic sequence is 9 and the 32nd term is 84. What is the 23rd term?
we can do 84-9 and get 75
now we have to do 32-5=27
so the common difference is 25/9
now we can count up from the 5th term to the 23rd term
that's 18 terms to count
18*25/9 is 50
so 50+9=59 as our answer
Good job, Guest!!!