The fifth term of an arithmetic sequence is 9 and the 32nd term is 84. What is the 23rd term?

we can do 84-9 and get 75

now we have to do 32-5=27

so the common difference is 25/9

now we can count up from the 5th term to the 23rd term

that's 18 terms to count

18*25/9 is 50

so 50+9=59 as our answer

Good job, Guest!!!