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The fifth term of an arithmetic sequence is 9 and the 32nd term is 84. What is the 23rd term?

 Feb 1, 2021
 #1
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we can do 84-9 and get 75 

now we have to do 32-5=27

 

so the common difference is 25/9

 

now we can count up from the 5th term to the 23rd term 

 

that's 18 terms to count 

 

18*25/9 is 50

 

so 50+9=59 as our answer

 Feb 2, 2021
 #2
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Good job, Guest!!!

Guest Feb 2, 2021

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