Arithmetic Sequence

Let the sequence be

a, a+d, a+2d, a+3d, a+4d

$\frac{a+3d}{a+d}=3 \qquad find \qquad \frac{a+4d}{a+2d}\\ 3a+3d=a+3d\\ 2a=0\\ a=0\\ so\\ \frac{a_5}{a_3}=\frac{a+4d}{a+2d}=\frac{4d}{2d}=2$

Just wanted to try this one, too...

a4 / a2   = 3

a4  = 3a2

a4  = a2 + 2d   ...so...

a2 + 2d  = 3a2

2d  = 2a2

d  = a2

And   a5 /a3  =

[ a2 + 3d  ] / [ a2 + d  ] =

[d + 3d ] / [ d + d ]

4d / 2d  =

2

This is what Melody got, as well !!!

Thanks! Both are correct! Thanks for your hard work!