Rewrite as: \((3 \times 25) + (3 \times 24) + (3 \times 23) + \cdot \cdot \cdot +(3 \times 4) + (3 \times 3) + (3 \times 2) + (3 \times 1) \)
Factor out the 3: \(3(1 + 2+3+4+5+ \cdot \cdot \cdot 22 + 23 + 24 + 25 )\)
The sum of the inside part is \(25 \times 26 \div 2 = 325\)
So the sum of everything is \(325 \times 3= \color{brown}\boxed{975}\)