What is the sum of three consecutive even integers if the sum of the first and third integers is $128$?

The numbers would be: 62 + 64 + 66 =192, and 62 + 66 = 128.

Let the first integer = N

So.....the 3rd integer is N + 4

And

N + N + 4 = 128 simplify

2N + 4 = 128 subtract 4 from both sides

2N = 124 divide both sides by 2

N = 62

N + 4 = 66

62 + 66 = 128