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a1 = 10

n = 3

Sn = 208

 

d, an =?

 Dec 27, 2016
edited by Guest  Dec 27, 2016

Best Answer 

 #1
avatar+36923 
+10

For an arithmetic sequence   Sn = n/2 (a1+an)

208 = 3/2(10+a3)

a3=128.66

 

10              a2                  128.66                (128.66+10)/2 = D  = 59.33

 

10        10+59.33         10 + 59.33+ 59.33

10         69.33                128.66

 

an then becomes       an= 10 + 59.33(n-1)          or     an = 59.33n - 49.33

 Dec 27, 2016
 #1
avatar+36923 
+10
Best Answer

For an arithmetic sequence   Sn = n/2 (a1+an)

208 = 3/2(10+a3)

a3=128.66

 

10              a2                  128.66                (128.66+10)/2 = D  = 59.33

 

10        10+59.33         10 + 59.33+ 59.33

10         69.33                128.66

 

an then becomes       an= 10 + 59.33(n-1)          or     an = 59.33n - 49.33

ElectricPavlov Dec 27, 2016

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