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# AS PHYSICS

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A length of cable of diameter 1.2mm is under a tension of 150N. Calculate the stress in the cable.

I got 1.33*108 but I am not sure that it is correct or not??

Dec 2, 2017

#1
+1

Stress = F/A     Area= pi x r^2 = pi x .6^2 = 1.13 mm^2

F=Force = 150 N  (given)

Stress is usually given in Pascals ( N/m^2)   so you will need to convert area to m^2

1.13 mm^2 = 11.3 x10^-7 m^2

Stress then becomes  F/A = 150 N / (11.3 x 10^-7 m^2) = 132629119 Pascals

So you are correct....but don't forget your UNITS.....Pascals (N/m^2)

Dec 2, 2017

#1
+1

Stress = F/A     Area= pi x r^2 = pi x .6^2 = 1.13 mm^2

F=Force = 150 N  (given)

Stress is usually given in Pascals ( N/m^2)   so you will need to convert area to m^2

1.13 mm^2 = 11.3 x10^-7 m^2

Stress then becomes  F/A = 150 N / (11.3 x 10^-7 m^2) = 132629119 Pascals

So you are correct....but don't forget your UNITS.....Pascals (N/m^2)

ElectricPavlov Dec 2, 2017
#2
+1

So it is possible to get a high very high value for stress, right??

Rauhan  Dec 2, 2017
#3
+2

Yes.....because this is a VERY thin cable supporting a large force, so the stress is quite high.   Good job!

ElectricPavlov  Dec 2, 2017