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as the limit of x--> -1 approaches 1/(1+x)^2 is the answer infinity?

 Dec 9, 2016
 #1
avatar+129840 
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See  graph here   :  https://www.desmos.com/calculator/z2500cohbm

 

 

 

cool cool cool

 Dec 9, 2016
 #2
avatar+118654 
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Thanks Chris,

It is always really good for people to see graphs.

I think it is really hard for people to grasp the concept of how algebra and graphs are related to one another.

The more graphs they are shown the more likely it is that the concept will be understood. :)

 

 

as the limit of x--> -1 approaches 1/(1+x)^2 is the answer infinity?

 

\(\displaystyle\lim_{x\rightarrow -1}\;\;\frac{1}{(1+x)^2}\)

 

Just think about this for a tick.

 

As x approaches -1 the denominator approaches zero but it will also ve positive.

As the denominator gets smaller and smaller, the fraction will become larger and larger.

So yes the limiti does equal +infiity.

 Dec 9, 2016

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