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Find all real numbers x that satisfy the equation (x-4)(x-8) = 12.

 Feb 10, 2019
 #1
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 (x-4)(x-8) = 12

 

Expand the left side

 

x^2 - 12x + 32 =  12        subtract 12 from both sides

 

x^2 - 12x + 20  =   0

 

Factor

 

(x  - 10 ) ( x - 2) = 0

 

Setting each factor to 0  and solving for x produces

 

x = 10    or  x  = 2

 

 

 

cool cool cool

 Feb 10, 2019

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