Find all real numbers x that satisfy the equation (x-4)(x-8) = 12.
(x-4)(x-8) = 12
Expand the left side
x^2 - 12x + 32 = 12 subtract 12 from both sides
x^2 - 12x + 20 = 0
Factor
(x - 10 ) ( x - 2) = 0
Setting each factor to 0 and solving for x produces
x = 10 or x = 2