+0  
 
0
33
1
avatar

Find all real numbers x that satisfy the equation (x-4)(x-8) = 12.

 Feb 10, 2019
 #1
avatar+98090 
+1

 (x-4)(x-8) = 12

 

Expand the left side

 

x^2 - 12x + 32 =  12        subtract 12 from both sides

 

x^2 - 12x + 20  =   0

 

Factor

 

(x  - 10 ) ( x - 2) = 0

 

Setting each factor to 0  and solving for x produces

 

x = 10    or  x  = 2

 

 

 

cool cool cool

 Feb 10, 2019

34 Online Users

avatar
avatar
avatar
avatar