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Kai and Jordan had 300 marbles altogether. Kai gave away 25% fewer marbles than Jordan. Jordan was left  with 50% as many as the number of marbles he gave away. Kai had 75% of the total number of marbles the boy left in the end. How many marbles did Kai have in the end?

 May 5, 2021
 #1
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There is a word missing in this sentence and I don't know what it is ??

Can you proof it please.

 

"Kai had 75% of the total number of marbles the boy left in the end."

 

I thought it was probably

"Kai had 75% of the combined total that the boys had left at the end"  

 But doing this I ended up with John having the initial number of 186 and 6/29 of a marble.

No one has 6/29 of a marble so the question, as I interpreted it, is not correct.

 May 10, 2021
edited by Melody  May 10, 2021
 #2
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Kai and Jordan had 300 marbles altogether. Kai gave away 25% fewer marbles than Jordan. Jordan was left with 50% as many as the number of marbles he gave away. Kai had 75% of the total number of marbles the boys left in the end. How many marbles did Kai have in the end?

 

ok I edited

Guest May 10, 2021
edited by Guest  May 10, 2021
 #4
avatar+113698 
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The ambiguity is still there.  Are you English as a second language?

anyway, I think you want me to interpret it the way that I did interpret it and I do not think that the fractions/proportions are possible.

Melody  May 10, 2021
edited by Melody  May 10, 2021
 #5
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That's what the question says

Guest May 10, 2021
 #3
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Please do not put 'asap' or similar in your questions.  It makes me less likely to answer. Your questions are not more important than anyone elses. 

 May 10, 2021
 #6
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See if you can find a logic error.   

J stands for the number or marbles Jordan has at the beginning.

 

  Given Kept Total
Jordan \(\frac{2J}{3}\) \(\frac{1J}{3}\) J
Kai \(\frac{J}{2}\) \(\frac{J}{9}\) \(\frac{11J}{18}\)
Total \(\frac{21J}{18}\) \(\frac{8J}{18}\) \(\frac{29J}{18}=300\\ J=186\frac{6}{29}\)
 May 10, 2021
 #9
avatar+113698 
+1

Continued in response to this post:

https://web2.0calc.com/questions/asap-i-am-upset-of-this

 

 

Ok I found my error, it was the middle square

 

 

  Given kept total
jordan \(\frac{2J}{3}\) J/3 J
Kai J/2 J 3J/2
Total 7J/6 4J/3 300

 

 

\(J+\frac{3J}{2}=300\\ \frac{5J}{2}=300\\ J=120\\ check\\ (7*120/6)+(4*120/3)=300\;\;correct\)

 

So Kai keeps  120 marbles (which is the total number that Jordan has in the beginning)

 

  given kept total
Jordan 80 40 120
Kai 60 120 180
Total 140 160 300
 May 20, 2021

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