+0

# Asap plz

0
109
1
+4

https://snipboard.io/C9A45r.jpg

May 6, 2021

$\sum_{n=1}^{33} \frac{1}{(3n-2)(3n+1)} = \frac{33}{100}$ because it has an asymptote that gets really close to $33.\overline{3}.$