Use the product-to-sum (NOT SUM-TO-PRODUCT) formulas to write the given expression as a product.
12sinπ6sinπ6
A. −6sinπ12
B. 6sinπ6+6cosπ6
C. 6−6cosπ12
D. 6+6cosπ12
sinasinb = 1/2 [cos ( a-b) -cos(a+b)]
= 1/2 * 12 ( cos 0 - cos pi/3)
6 - 6 cos pi/3 <============== Don't see that as an answer ....they MIGHT have intended C.