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12SinR = 17Sin(106 - R)
find R
 Aug 11, 2013
 #1
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12*sin(R) = 17*sin(106-R)
12*sin(R)/17 = sin(106)*cos(R)-cos(106)*sin(R)
12/17 = [sin(106)*cos(R)-cos(106)*sin(R)]/sin(R)
12/17 = [sin(106)*cos(R)]/sin(R) - [cos(106)*sin(R)]/sin(R) = sin(106)*cot(R) - cos(106)
=> [cos(106)+12/17]/sin(106) = cot(R)
= cot(106)+12/(17*sin(106)) = cot(R)
=> R = acot(cot(106)+12/[17*sin(106)])
 Aug 11, 2013

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