The quadratic function which take value 41 at x=-2 and the value 20 at x=5
find A,B,C
+130514 This cannot be be precisely determined ....to see why, we have
41 = A(-2)^2 + B(-2) + C → 41 = 4A - 2B + C (1)
20 = A(5)^2 + B(5) + C → 20 = 25A + 5B + C (2)
But, we have more variables than equations......in this situation, we will have an infinite number of solutions
[We need one more point and function value at that point to obtain a solution ]
