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Assume that f(3) = 4. Name a point that must be on the graph of y=\tfrac12f\left(\tfrac{x}{2}\right).

 Nov 16, 2014

Best Answer 

 #1
avatar+130511 
+5

So, for some "x,"  f (x) = 4  ..... and this "x" = 3

So "x/2" would be   3/2  ....  and the "1/2" in front would make the original graph half as high at this point.

So...the point would be (3/2, 2)

 

 Nov 16, 2014
 #1
avatar+130511 
+5
Best Answer

So, for some "x,"  f (x) = 4  ..... and this "x" = 3

So "x/2" would be   3/2  ....  and the "1/2" in front would make the original graph half as high at this point.

So...the point would be (3/2, 2)

 

CPhill Nov 16, 2014
 #2
avatar
0

Sorr, but this was wrong

 Nov 16, 2014
 #3
avatar+33661 
+1

If x = 6, then y = (1/2)f(6/2) = (1/2)f(3) = (1/2)*4 = 2

so (6, 2) is on the graph of y = (1/2)f(x/2)

.

 Nov 16, 2014

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