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Assuming that x does not equal zero, translate the following according to exponent law:

5x/5x

 Dec 1, 2016
 #1
avatar+15000 
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Assuming that x does not equal zero, translate the following according to exponent law:
5x/5x

 

\(x\ {\in \mathbb R }\)\(\) \ 0

 

\(\frac{5x}{5x}=5^1\times x^1 \times 5^{-1}\times x^{-1}=5^{1-1}\times x^{1-1}\)

 

\(=5^0\times x^0 =1\times 1=1\)

 

\(\frac{5x}{5x}=1\)  laugh  !

 Dec 1, 2016
 #2
avatar+30 
0

so much unneccesarry work to just divide 5x by 5x 

einsteinofmath  Dec 1, 2016

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