Assuming that x does not equal zero, translate the following according to exponent law:

Assuming that x does not equal zero, translate the following according to exponent law:
5x/5x

$x\ {\in \mathbb R }$ \ 0

$\frac{5x}{5x}=5^1\times x^1 \times 5^{-1}\times x^{-1}=5^{1-1}\times x^{1-1}$

$=5^0\times x^0 =1\times 1=1$

$\frac{5x}{5x}=1$    !