The graph of f(x) = (2x)/(3x^2 - 6x - 14) has vertical asymptotes x = a and x = b, and horizontal asymptote y = c. Find a + b + c.
(2x) / ( 3x^2 - 6x - 14)
We have a lower power polynomial over a higher power polynomial......this sets up a horizontal asymptote at y = 0
The vertical asymptotes will be where 3x^2 - 6x - 14 = 0
By Vieta the sum of the asymptotes = the sum of the roots of this poynomial = a + b = - (-6) / 3 = 2
a + b + c = 0 + 2 = 2