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At noon the armadillo left the wild Kingdom and headed north at 3 km/h. two hours later the raccoon left the same kingdom and headed south at 5 km/h. at what time will the animals be 38 km apart?

 Mar 4, 2020
 #1
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Hint: Pythagorean theorem and algebra

 Mar 4, 2020
 #2
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the arm   has a 2 hr headstart    3 km/hr x 2 hr = 6 km   before racoon sets out

 

then the two critters are separating at    3 + 5 = 8 km / hr

 

6 km  +   8km/hr  *  x hr = 38 km

x= 4 hr   after the racoon left       or 6 hours after the arm left        noon + 6hr =  1800    or   6 pm

 Mar 4, 2020
edited by ElectricPavlov  Mar 4, 2020

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