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(b^5)^2=b^7

 Jun 11, 2015

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 #1
avatar+14538 
+5

$${\left({{\mathtt{b}}}^{{\mathtt{5}}}\right)}^{{\mathtt{2}}} = {\left({\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}\right)}^{{\mathtt{2}}}$$ = $${\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}$$ = $${{\mathtt{b}}}^{{\mathtt{10}}}$$

 

$${\left({{\mathtt{b}}}^{{\mathtt{5}}}\right)}^{{\mathtt{2}}} = {{\mathtt{b}}}^{{\mathtt{10}}}$$

 

$${{\mathtt{b}}}^{{\mathtt{5}}}{\mathtt{\,\times\,}}{{\mathtt{b}}}^{{\mathtt{2}}} = {{\mathtt{b}}}^{{\mathtt{7}}}$$

.
 Jun 11, 2015
 #1
avatar+14538 
+5
Best Answer

$${\left({{\mathtt{b}}}^{{\mathtt{5}}}\right)}^{{\mathtt{2}}} = {\left({\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}\right)}^{{\mathtt{2}}}$$ = $${\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{b}}$$ = $${{\mathtt{b}}}^{{\mathtt{10}}}$$

 

$${\left({{\mathtt{b}}}^{{\mathtt{5}}}\right)}^{{\mathtt{2}}} = {{\mathtt{b}}}^{{\mathtt{10}}}$$

 

$${{\mathtt{b}}}^{{\mathtt{5}}}{\mathtt{\,\times\,}}{{\mathtt{b}}}^{{\mathtt{2}}} = {{\mathtt{b}}}^{{\mathtt{7}}}$$

radix Jun 11, 2015

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