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Find the largest possible positive integer x10 less than 202110 such that d(x11)2=4d(x13).

 

Notation clarification: xk is x in base k

d(xk) is the sum of the digits of x in base k

 Mar 5, 2021
 #1
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Note: This can easily be done with simple coding.

 Mar 5, 2021

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