+0  
 
+1
726
1
avatar+586 

Suppose that p is prime and \(1007_p+306_p+113_p+125_p+6_p=142_p+271_p+360_p\). How many possible values of p are there?

 Aug 8, 2019
 #1
avatar
0

p can be 2, 3, 11, and 19, so there are four possible values of p.

 Nov 21, 2019

3 Online Users

avatar