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Please help, i need this extra credit points.

Guest Feb 28, 2017
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I answered this one awhile back, but.....I'll go through it again

 

We need to use the Law of Cosines to first determine the distance from the pitcher to third base.....so we have

 

D   = √ [ 47^2 + 63^2 - 2(47)(63) cos(45) ] 

 

So......calling the angle "A"  that the pitcher must turn, we have

 

sin A / 63  =  sin (45) / D

 

sin A  =   63 * sin (45) / √ [ 47^2 + 63^2 - 2(47)(63) cos(45) ]

 

arcsin ( 63 * sin (45) / √ [ 47^2 + 63^2 - 2(47)(63) cos(45) ] )  = A  ≈ 86.8491°

 

 

cool cool cool

CPhill  Mar 1, 2017

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