Xavier writes down a three-digit positive integer. Youssef writes a in front of the digits of Xavier's number, so that the resulting number has four digits. If this four-digit number is times as large as Xavier's original number, what number did Xavier write down?

So here's my approach:

we know xaviers number is in the range of 100-999

and we know it has to be a multiple of 13

and the number we are trying to find is between 1000-9999

and it has to start with a 3.

Jasonkiln Mar 19, 2023

#1**0 **

"If this four-digit number is times as large as Xavier's original number, what number did Xavier write down"? How many times larger?

Guest Mar 19, 2023

#3**0 **

Let Xavier's three-digit number be represented as $ABC$, where $A$, $B$, and $C$ are digits representing the hundreds, tens, and ones digits, respectively. Then, Youssef's four-digit number is $3ABC$.

Since the four-digit number is 13 times as large as the original number, we have:

$$3ABC = 13 \cdot ABC$$

Simplifying this equation, we get:

$$3000 + 100A + 10B + C = 13(100A + 10B + C)$$

Expanding the right side, we get:

$$3000 + 100A + 10B + C = 1300A + 130B + 13C$$

Simplifying this equation further, we get:

$$1170A + 120B = 2999$$

Since $A$ and $B$ are digits, the left-hand side of this equation is an integer between 0 and 999. Therefore, the only possible value for $A$ is 2, and the only possible value for $B$ is 4. Substituting these values into the equation, we get:

$$1170(2) + 120(4) = 2520 + 480 = 2999$$

Therefore, Xavier's original number is $ABC = \boxed{240}$.

Guest Mar 19, 2023