Basketball

Well ....two of the positions are "set"

So.....  we just want to choose any 3 of the remaining  10 players  = C(10,3)  = 120  different lineups

Coach Grunt has to choose 3 players from the 10 players that are remaining after Ace and Zeppo have been placed in the lineup. The order in which the players are chosen doesn't matter, so the answer is $\binom{10}{3} = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = \boxed{120}.$