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4^3/[8(6^0-2^1]

 Nov 7, 2015
 #1
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4^3/[8(6^0-2^1]

 

Simplify the following:
4^3/(8 (6^0-2^1))

6^0 = 1:
4^3/(8 (1-2))

1-2 = -1:
4^3/(8×-1)

4^3 = 4×4^2:
4×4^2/(8 (-1))

4^2 = 16:
(4×16)/(8 (-1))

4×16  =  64:
64/(8 (-1))

64/8 = (8×8)/8 = 8:
8/(-1)

Multiply numerator and denominator of 8/(-1) by -1:
Answer: | 
| -8

 Nov 7, 2015

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