The product of two numbers (1-10) is two times as big as the sum of the numbers, what are the numbers?
Let one number = n
Then the other is 10 - n ......and we have
n(10 -n) = 2 [ n + 10 - n ] simplify
10n -n^2 = 2 [10]
10n - n^2 = 20 rearrange as
n^2 - 10n + 20 = 0
Solving this. the two numbers are 5 + √5 and 5 - √5
