+4 An airplane is flying at an altitude of 10,000 ft. The airport at which it is scheduled to land is 50 mi away. Find the average angle at which the airplane must descend for landing. Round your answer to the nearest degree.
+36916 10000 ft = 10000/5280 mi = 1.8939 mi
Tan (angle ) = 1.8939 mi / 50 mi = .037878
arctan(.037878) = 2.169 degree angle of descent
