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avatar+118723 

i cannot answer your question - the forum code will not allow it.

I think it is because you have put in a title that is not in ordinary print.  Sometimes this happens.

 

Your question is 

$$\frac{x}{2z}-2b=0$$

Lösungsmenge     $$\left\{\dfrac{0,3}{b}\right\}$$       

 

-------------------------------------

I do not understand what you mean by

 

Solution set       $$\left\{\dfrac{0,3}{b}\right\}$$       ???

 

-----------------------------

 

 

Ich   verstehe   nicht was   du   meinst

Lösungsmenge     $$\left\{\dfrac{0,3}{b}\right\}$$       ???

 Apr 13, 2015

Best Answer 

 #1
avatar+118723 
+3

Maybe a person who speaks French or German might be able to help with the translation ?

Can anyone help, it is not making sense to me.  

Peut-être   une   personne   qui   parle  le  Français   ou   l'allemand   pourrait   être   en mesure d'aider   à   la   traduction   ?

Quelqu'un peut aider, il ne fait pas sens pour moi.  

----------------------------------------------------------------------

I am getting criptic private messages here.  Mmm

 

Servus, 


fraction bar -2b= 0 
5*z 

z=???

 

$$\frac{x}{2z}-2b=0$$

 

$$\\\frac{3}{-2b}=0\\$$      This is impossible - you cannot divide 3 by ANYTHING and get 0!

 Apr 13, 2015
 #1
avatar+118723 
+3
Best Answer

Maybe a person who speaks French or German might be able to help with the translation ?

Can anyone help, it is not making sense to me.  

Peut-être   une   personne   qui   parle  le  Français   ou   l'allemand   pourrait   être   en mesure d'aider   à   la   traduction   ?

Quelqu'un peut aider, il ne fait pas sens pour moi.  

----------------------------------------------------------------------

I am getting criptic private messages here.  Mmm

 

Servus, 


fraction bar -2b= 0 
5*z 

z=???

 

$$\frac{x}{2z}-2b=0$$

 

$$\\\frac{3}{-2b}=0\\$$      This is impossible - you cannot divide 3 by ANYTHING and get 0!

Melody Apr 13, 2015
 #2
avatar+118723 
0

Chris, do you understand what Berg... might want.

He is all disappointed that I cannot understand what his question is and he is going to pack up and go back to the German forum. :(

 Apr 13, 2015

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