#1**0 **

how much smaller is 1/h than h

\(h-\frac{1}{h}=\frac{h^2-1}{h}=\frac{(h+1)\times(h-1)}{h}\)

\(\frac{1}{h} \ is \ \frac{h^2-1}{h} \ smaller \ than \ h.\)

This is nonsense but mathematically correct. Or?

!

asinus
Mar 2, 2017

#2**+1 **

It could be asking how many *times* smaller 1/h is.

It could be asking what you have to multiply 1/h by to get h.

In that case:

(1/h)x=h

x=h^{2}

So you have to multiply 1/h by h^{2} to get h.

1/h is h^{2} times smaller than h.

Either way is possible. I don't really know what the question is asking for.

hectictar
Mar 2, 2017