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How do I change a base ten number to binary number?

 Mar 29, 2016
edited by gibsonj338  Mar 29, 2016
 #1
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This is HOW you do it. Ex. convert 125 from base 10(decimal) to base 2(binary):

125/2=62.5 if it leaves a fraction, then it is a 1. You write from R to L. Next:

62/2=31 if it leaves no fraction, then it is a o

31/2=15.5 it leaves a fraction, then it is a 1

15/2=7.5   ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,  1

7/2=3.5,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, 1

3/2=1.5,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,  1

The final 1 comes down as it is a,,,,,,,,,,,,,, 1

Then write it down from to top to bottom and going from right to left, thus:

1111101=125. Or, you can start from the bottom to the top and going from left to right, which is the same thing: 1111101=125. And that is it.

 Mar 29, 2016
 #2
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Here's an example....suppose we want to change 39 base 10 to a binary number....we divide repetitively as follows until we have a fraction < 1......

 

39 / 2   =    19  +  remainder 1

19/2    =       9  + remainder 1

9/2     =        4  + reminader 1

4/2  =           2  +  remainder 0

2/2  =           1   +  remainder 0

1/2  =                    remainder 1

 

Now......write  the remainders  from bottom to top in order  =  100111

 

This is the base 2 representation of 39.....

 

Proof

 

1*2^5  + 0 *2^4 + 0*2^3 + 1*2^2 + 1*2^1  + 1*2^0  =

 

32 + 0 + 0 + 4 + 2 + 1  =

 

32 + 4 + 2 + 1  =

 

39

 

 

cool cool cool

 Mar 29, 2016

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