A family has six children. Find the probability that there are fewer boys than girls
Probability of 6 girls = (1/2)^6
Probability of 5 girls, 1 boy = C(6,5)(1/2)^6
Probability of 4 girls, 2 boys = C(6,4) (1/2)^6
Total probability = (1/2)^6 + C(6,5)(1/2)^6 + C(6,4) (1/2)^6 = 11/32 ≈ 34.4%
