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A family has six children. Find the probability that there are fewer boys than girls

Guest Oct 4, 2017
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Probability of 6 girls  =   (1/2)^6

 

Probability of 5 girls, 1 boy =   C(6,5)(1/2)^6

 

Probability of 4 girls, 2 boys  = C(6,4) (1/2)^6

 

Total probability  =  (1/2)^6 +  C(6,5)(1/2)^6 +   C(6,4) (1/2)^6  =  11/32 ≈ 34.4%

 

 

cool cool cool

CPhill  Oct 4, 2017

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