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Let  a and b be real numbers such that \(a^3 + 3ab^2 = 679\) and \(3a^2 b + b^3 = -652\). Find a+b

 Mar 13, 2019
 #1
avatar+118609 
+3

Hint:

Expand     (a+b)^3     and see what you get.

 

 

Please no one answer over me.

 Mar 13, 2019

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