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For what real values of $c$ is $x^2 - 8x - 14x + c$ the square of a binomial?

 Jan 1, 2024
 #1
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x^2  - 8x - 14x + c

 

x^2  - 22x  + c

 

x^2 - 22x + (22/2)^2

 

x^2   - 22x + 11^2

 

x^2 - 22x + 121

 

( x - 11)^2

 

So  c   = 121

 

cool cool cool

 Jan 2, 2024

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