+0  
 
0
16
1
avatar+1348 

For what real values of $c$ is $x^2 - 8x - 14x + c$ the square of a binomial?

 Jan 1, 2024
 #1
avatar+129840 
+1

x^2  - 8x - 14x + c

 

x^2  - 22x  + c

 

x^2 - 22x + (22/2)^2

 

x^2   - 22x + 11^2

 

x^2 - 22x + 121

 

( x - 11)^2

 

So  c   = 121

 

cool cool cool

 Jan 2, 2024

1 Online Users