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# binomial

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Find a so that ax^2 + 16x + 9 is the square of a binomial.

Nov 29, 2020

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The binomial squared must be in the form  $$(\sqrt ax+3)^2$$

When expanded this is $$ax^2+6\sqrt ax+9$$   which means that  $$6\sqrt a=16$$   or  $$a=\frac{64}{9}$$

Nov 29, 2020