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Find a so that ax^2 + 16x + 9 is the square of a binomial.

 Nov 29, 2020
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The binomial squared must be in the form  \((\sqrt ax+3)^2\)

 

When expanded this is \(ax^2+6\sqrt ax+9\)   which means that  \(6\sqrt a=16\)   or  \(a=\frac{64}{9}\)

 Nov 29, 2020

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