+4609 On Tuesday, I worked \(t+1\) hours and earned \(3t-3\) dollars per hour. My friend Andrew worked 3t-5 hours but only earned t+2 dollars an hour. At the end of the day, I had earned two dollars more than he had. What is the value of t?
+502 I am not 100% sure if this answer is correct but is the answer \(\frac{7}{6}\)
+502 nevermind I got it.
\((t+1)(3t-3)=(3t-5)(t+2)\)
Expanding gives
\(3t^2-3t+3t-3= 3t^2+6t-5t-10\)
Get the like terms together
\(3t^2-3t^2 -3t+3t +5t - 6t=-10+3\)
3t2 cuts out and the remaining equals to -t but u are looking for a positive t so so multiply both sides by (-).
therefore this gives
\(t=10-3\)
\(t=7\)
So on Tuesday, u worked 8 hours and got 18$ and Andrew worked 16 hours and got 9 dollars. And also the question should be
'At the end of the day, I had earned two times more than he had. What is the value of t?'
+128399 Hours * Rate per hour = Total Amt
So
(t + 1) (3t - 3) = (3t - 5)(t + 2) + 2 simplify
3t^2 + 3t - 3t - 3 = 3t^2 - 5t + 6t - 10 + 2
-3 = 1t - 8 add 8 to both sides
5 = 1t
5 = t
Check
(5 + 1)(3*5 - 3) = (3(5) - 5 ) ( 5 + 2) + 2 ???
(6)(12) = (10)(7) + 2
72 = 70 + 2
So.....t = 5 is correct
