The NYPD has 35,000 members. Suppose two members are chosen at random. In how many different ways can they be chosen?
We want to choose any 2 of the 35,000
C(35000, 2) = 612,482,500 ways (pairs)
Sorry....footballgirl....it doesn't appear that any of the choices you have been given are correct....
Sir CPill’s answer is right. Normally, in selecting combinations the order of selection is irrelevant. (XY is the same as YX).
P(35000, 2) = 1,224,965,000
This implies the enumeration counts the order of selections in addition to the combinations. In other words, order matters. The question should state that, if that is the case. If it does not, then none of the answer choices is correct. You should let your teacher know.