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infinity*0
 Nov 22, 2013
 #1
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undefined (so I am told)
 Nov 22, 2013
 #2
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Okay. Anything multiplied by 0 is 0
MATH GOD OUT.
 Nov 22, 2013
 #3
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According to calculus, (inifnity*0) is actually what is considered an indeterminate form. Which means that if cannot have an answer. If attempt to find an answer you can get very many different things.

lim n->∞ (n * sin(1/n))
= lim n->0 sin(n) / n
= 1

The explanation if this is that sin of 1 /n as n approaches infinity turns out to approach 0. so then n is infinity as n approaches infinity and if you were to evaluate that limit you get infinity*0 = 1. But, then you go and try

lim n->∞ ln(n/(n+1))
= lim n->∞ ln( 1 / (1 + 1/n))
[and since 1/n goes to 0,]
= ln(1 / (1+0))
= ln(1)
= 0

Which also results, while evaluating the limit, as infinity*0 = 1 in this case. The point is there isn't an answer
 Nov 22, 2013
 #4
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dear bob, this is a trick question your math teacher is trying to waste your precious time on this problem i suggest you stab her with an elephant tusk
 Nov 28, 2013

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