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Find all values of $x$ such that $\dfrac{x}{x+4} = -\dfrac{9}{x+3}$. If you find more than one value, then list your solutions in increasing order, separated by commas.

Thanks, mark

EDIT: why has this been flagged sad what did I do?

 Apr 20, 2019
edited by Guest  Apr 20, 2019
 #1
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\( \dfrac{x}{x+4} = -\dfrac{9}{x+3}\)

 

Cross- multiply

 

x(x + 3)  = - 9 ( x + 4)

 

x^2 + 3x  = - 9x - 36       rearrange as

 

x^2 + 12x + 36  =  0       factor as

 

(x + 6)^2  =  0

 

This implies that  x  must be  - 6

 

Sorry  that your post was flagged......I don't know why.....

 

 

cool cool cool

 Apr 20, 2019

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