Find all values of $x$ such that $\dfrac{x}{x+4} = -\dfrac{9}{x+3}$. If you find more than one value, then list your solutions in increasing order, separated by commas.Thanks, markEDIT: why has this been flagged what did I do?
\( \dfrac{x}{x+4} = -\dfrac{9}{x+3}\)
Cross- multiply
x(x + 3) = - 9 ( x + 4)
x^2 + 3x = - 9x - 36 rearrange as
x^2 + 12x + 36 = 0 factor as
(x + 6)^2 = 0
This implies that x must be - 6
Sorry that your post was flagged......I don't know why.....
what did I do?
