I need a natural number in each box (bottom row is 4 boxes, then 3, 2, 1 in a tower) so that each number above the bottom row is the sum of the two numbers immediately underneath. Find the largest number of odd numbers I can use.

I fixed my typo from earlier, I apologize.

I find 5 odds but the answer is supossed to be 7. I am trying odd/even sums to get odd numbers.

MacTyBoys Feb 22, 2019