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Brandon, Brenda, and Brad are triplets. They were born 3 years after their sister, Janice. This year, the product of their ages is 60 687 greater than the sum of their ages. How old is Janice?

 Apr 12, 2020
 #1
avatar+23689 
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Question is unclear   60 687 ?     The product of 'their' ages    .....   who?   The triplets only...or all four of the siblings?

 Apr 12, 2020
 #2
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Let the 3 triplet's age =B years each
Janice's age =B+3 years
(B+3) * B^3 =(B+3) + 3B + 60687, solve for B
B^4 + 3B^3 - 4B - 60690 =0
(B - 15)*(B^3 + 18B^2 + 270B + 4046) =0
B =15 - Years - the age of the 3 triplets.
15 + 3 = 18 Years - Janice's age.

 Apr 12, 2020
 #3
avatar+30087 
+1

This only makes sense if the the product and sum refer to all four siblings:

 

 Apr 12, 2020

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