Brandon, Brenda, and Brad are triplets. They were born 3 years after their sister, Janice. This year, the product of their ages is 60 687 greater than the sum of their ages. How old is Janice?
Question is unclear 60 687 ? The product of 'their' ages ..... who? The triplets only...or all four of the siblings?
Let the 3 triplet's age =B years each
Janice's age =B+3 years
(B+3) * B^3 =(B+3) + 3B + 60687, solve for B
B^4 + 3B^3 - 4B - 60690 =0
(B - 15)*(B^3 + 18B^2 + 270B + 4046) =0
B =15 - Years - the age of the 3 triplets.
15 + 3 = 18 Years - Janice's age.