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pH is 4.46 how to ''un-log'' to get concentration 3.47x10^5
 Nov 14, 2013
 #1
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What kind of math is this?
 Nov 14, 2013
 #2
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pH = -log [H3O+]

and therefore

[H3O+] = 10^-pH

or in your case [H3O+] = 10^-4.46
 Nov 14, 2013

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